Limestone with a mass of 100 g, containing 84% calcium carbonate CaCO3, interacts with the required

| March 10, 2021 | education

Limestone with a mass of 100 g, containing 84% calcium carbonate CaCO3, interacts with the required amount of hydrochloric acid HCl. Calculate the mass of the resulting carbon monoxide (IV).

1. Let’s compose the equation of the proceeding reaction:

CaCO3 + 2HCl = CaCl2 + H2O + CO2 ↑;

2. Determine the mass of calcium carbonate contained in limestone:

m (CaCO3) = w (CaCO3) * m (limestone) = 0.84 * 100 = 84 g;

3. Find the chemical amount of calcium carbonate:

n (CaCO3) = m (CaCO3): M (CaCO3);

M (CaCO3) = 40 + 12 + 3 * 16 = 100 g / mol;

n (CaCO3) = 84: 100 = 0.84 mol;

4. Set the amount of carbon dioxide released:

n (CO2) = n (CaCO3) = 0.84 mol;

5. Calculate the mass of carbon monoxide:

m (CO2) = n (CO2) * M (CO2);

M (CO2) = 12 + 2 * 16 = 44 g / mol;

m (CO2) = 0.84 * 44 = 36.96 g.

Answer: 36.96 g.



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