Line segments AB and CD are diameters of one circle Find angle BCD if BAC = 35 °

The inscribed angle BAC, according to the condition, is equal to 35, then the degree measure of the BC arc, on which the angle rests, is equal to: BC arc = 2 * 35 = 70.

Since CD is the diameter of the circle, the degree measure of the arc CBD = 360/2 = 180.

Then the arc BD = 180 – 70 = 110.

The inscribed angle BCD rests on the arc BD, then the angle BCD is equal to half the degree measure of the arc BD.

Angle ВСD = 110/2 = 55.

Answer: The BCD angle is 55.