Line y = kx + b passes through points A (1; -2) and B (-3; -10). Equate this straight line.

If the graph of the function y = kx + b passes through the point O (x1; y1), then the following relation must be satisfied:
y1 = k * x1 + b.
According to the condition of the problem, the graph of the straight line y = kx + b passes through the point A (1; -2), therefore, we can write:
-2 = k * 1 + b.
It is also known that the graph of the straight line y = kx + b passes through the point B (-3; -10), therefore, we can write:
-10 = k * (- 3) + b.
We solve the resulting system of equations. Substituting into the second equation the value b = -2 – k from the first equation, we get:
-10 = k * (- 3) + -2 – k.
We solve the resulting equation:
k * 4 = 10 – 2;
k * 4 = 8;
k = 8/4;
k = 2.
Knowing k, we find b:
b = -2 – k = -2 – 2 = -4.

Answer: the straight line y = 2x – 4 passes through the points A (1; -2) and B (-3; -10).