Liquid drips from a round hole in a bowl. The mass of 100 drops is 2 g. What is the surface tension of the liquid

Liquid drips from a round hole in a bowl. The mass of 100 drops is 2 g. What is the surface tension of the liquid if the diameter of the drop neck before separation is 1.2 mm?

Given:
M = 2 * 10 ^ -3 kg;
N = 100;
d = 1.2 * 10 ^ -3 m;
Decision:
Let us write down the condition for droplet separation:
m1 * g = σ * L;
L = π * d = 2 * π * R;
Substitute the expression for the L value;
m1 * g = σ * π * d = 2 * π * R;
We print σ;
σ = M * g / N * π * d;
σ = 20 * 10 ^ -3 / 50 * 3.14 * 1.2 * 10 ^ -3 = 10.6 * 10 ^ -2 N / m;
ANSWER: THE SURFACE TENSION OF THE LIQUID IS EQUAL 10.6 * 10 ^ -2 N / m;