Loads are suspended at a distance of 2m from the fulcrum. One weight acts with a force of 6N.

| July 23, 2021 | education

Loads are suspended at a distance of 2m from the fulcrum. One weight acts with a force of 6N. How much force must be applied at a distance of 4m to keep the lever in balance?

Given:

a = 2 meters – the distance from the fulcrum to the place of suspension of the first load;

P1 = 6 Newtons – the weight of the first weight;

b = 4 meters – the distance at which the second load must be suspended (from the fulcrum).

It is required to determine P2 (Newton) – the weight of the second weight.

Since it is not specified in the problem statement, we assume that the lever itself has no weight. Then, to find the weight of the second weight, you need to use the following formula:

P1 * a = P2 * b;

P2 = P1 * a / b = 6 * 2/4 = 6/2 = 3 Newton.

Answer: at a distance of 4 meters, a force equal to 3 Newton must be applied.



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