Locomotive with a power of 600W, moving evenly travels 20s 200m. What is its thrust force?

Task data: N (power of a given locomotive) = 600 W; t (duration of movement of the locomotive) = 20 s; S (distance traveled) = 200 m.
We express the traction force of a given locomotive from the formula: N = F * V, whence F = N / V = N / (S / t) = N * t / S.
Let’s calculate: F = 600 * 20/200 = 1200/200 = 60 N.
Answer: The traction force of a given locomotive is 60 N.



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