Mх – 40 g of cold water, the temperature of which is tx = 20 ° C, and mg = 60 g of hot water

Mх – 40 g of cold water, the temperature of which is tx = 20 ° C, and mg = 60 g of hot water, the temperature of which is tr = 50 ° C, are adhered to the calorimeter. Determine the temperature of the mixture of hot and cold water / s, established in the calorimeter.

Decision:
0.04 * (Ttr-20) = 0.06 * (50-Ttr)
0.04Trp-0.8 = 3-0.06Trp
3-0.06 Ttr-0.04 Ttr-0.8 = 0
2.2-0.1 Ttr = 0
0.1Ttr = 2.2
Ttr = 22 ° C
Answer = 22 ° C