Macca Al (1% impurities) which is necessary to isolate 33.6 liters with 4 from the H2SO4 solution.

Given:
ω approx. = 1%
V (SO2) = 33.6 l
To find:
m tech. (Al) -?
Decision:
1) Write the reaction equation:
2Al + 6H2SO4 => Al2 (SO4) 3 + 3SO2 ↑ + 6H2O;
2) Calculate the amount of substance SO2:
n (SO2) = V (SO2) / Vm = 33.6 / 22.4 = 1.5 mol;
3) Determine the amount of Al substance:
n (Al) = n (SO2) * 2/3 = 1.5 * 2/3 = 1 mol;
4) Calculate the mass of pure Al:
m clean (Al) = n (Al) * M (Al) = 1 * 27 = 27 g;
5) Calculate the mass fraction of Al:
ω (Al) = 100% – ω approx. = 100% – 1% = 99%;
6) Calculate the mass of technical Al:
m tech. (Al) = m pure. (Al) * 100% / ω (Al) = 27 * 100% / 99% = 27.3 g.
Answer: The mass of Al is 27.3 g.