Magnesium chloride is reacted with 10.6 g of sodium carbonate. Find the mass of the sediment formed.

The formed precipitate is magnesium carbonate, MgCO3.

Let’s write the reaction equation:

MgCl2 + Na2CO3 = MgCO3 ↓ + 2NaCl

Let’s find the amount of sodium carbonate substance:

v (Na2CO3) = m (Na2CO3) / M (Na2CO3) = 10.6 / 106 = 0.1 (mol).

According to the reaction equation, 1 mol of MgCO3 is formed per 1 mol of Na2CO3, therefore:

v (MgCO3) = v (Na2CO3) = 0.1 (mol).

Thus, the mass of the resulting precipitate of magnesium carbonate:

m (MgCO3) = v (MgCO3) * M (MgCO3) = 0.1 * 84 = 8.4 (g).

Answer: 8.4 g.