Magnesium in the amount of substance 0.1 mol interacts with oxygen, determine the volume of oxygen

Magnesium in the amount of substance 0.1 mol interacts with oxygen, determine the volume of oxygen and the mass of magnesium oxide.

1. Let’s write the equation of interaction of magnesium with oxygen:

2Mg + O2 = 2MgO;

2.in the equation, the stoichiometric coefficients of magnesium, oxygen and magnesium oxide are related as 2: 1: 2, we determine the chemical amounts of oxygen and oxide:

n (O2) = n (Mg): 2 = 0.1: 2 = 0.05 mol;

n (MgO) = n (Mg) = 0.1 mol;

3.Calculate the volume of oxygen:

V (O2) = n (O2) * Vm = 0.05 * 22.4 = 1.12 L;

4.Calculate the mass of the resulting oxide:

m (MgO) = n (MgO) * M (MgO);

M (MgO) = 24 + 16 = 40 g / mol;

m (MgO) = 0.1 * 40 = 4 g.

Answer: 1.12 L, 4 g.