Magnesium oxide was added to 160 g of a nitric acid solution containing 10% HNO3.

Magnesium oxide was added to 160 g of a nitric acid solution containing 10% HNO3. Calculate the mass of the resulting water.

2HNO3 + MgO = Mg (NO3) 2 + H2O.
1) The mass of the substance of nitric acid in its solution is equal to: 160 * 10/100 = 16g.
2) The molar mass of nitric acid is: 1 + 14 + 16 * 3 = 63.
3) The amount of nitric acid substance is: 16/63 = 0.25 mol.
4) The amount of water substance is: 0.25 * 2 = 0.5 mol (determined by the reaction equation).
5) Molar mass of water: 1 * 2 + 16 = 18.
6) The mass of water: 18 * 0.5 = 9g – the answer.



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