Magnesium oxide weighing 10 g was treated with a nitric acid solution. What mass of salt did this produce?

univerkov | January 17, 2021 | education

Given:
m (MgO) = 10 g
To find:
m (Mg (NO3) 2)
Decision:
MgO + 2HNO3 = Mg (NO3) 2 + H2O
n (MgO) = m / M = 10 g / 40 g / mol = 0.25 mol
n (MgO): n (Mg (NO3) 2) = 1: 1
n (Mg (NO3) 2) = 0.25 mol
m (Mg (NO3) 2) = n * M = 0.25 mol * 148 g / mol = 37 g
Answer: 37 g

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