Magnesium was treated with 30 g of sulfuric acid. Calculate the amount of hydrogen evolved.

Magnesium interacts with sulfuric acid. In this case, magnesium sulfate is synthesized and hydrogen gas is released. This reaction is described by the following chemical reaction equation:

Mg + H2SO4 = MgSO4 + H2;

In accordance with the coefficients of the equation, when 1 mol of magnesium is dissolved, 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount of sulfuric acid. To do this, divide the available weight of the acid by the weight of 1 mole of acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 30/98 = 0.306 mol;

The same amount of hydrogen will be synthesized.

We calculate its volume, for this we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters):

V H2 = 0.306 x 22.4 = 6.854 liters;

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