# Magnesium was treated with 30 g of sulfuric acid. Calculate the amount of hydrogen evolved.

January 30, 2021 | education

| Magnesium interacts with sulfuric acid. In this case, magnesium sulfate is synthesized and hydrogen gas is released. This reaction is described by the following chemical reaction equation:

Mg + H2SO4 = MgSO4 + H2;

In accordance with the coefficients of the equation, when 1 mol of magnesium is dissolved, 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount of sulfuric acid. To do this, divide the available weight of the acid by the weight of 1 mole of acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 30/98 = 0.306 mol;

The same amount of hydrogen will be synthesized.

We calculate its volume, for this we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters):

V H2 = 0.306 x 22.4 = 6.854 liters;

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