# Magnesium weighing 16.8 g was placed in an excess of hydrochloric acid.

**Magnesium weighing 16.8 g was placed in an excess of hydrochloric acid. Determine the volume of the allocated hydrogen**

Magnesium interacts with hydrochloric acid. In this case, magnesium chloride is synthesized and hydrogen gas is released. This reaction is described by the following chemical reaction equation:

Mg + 2HCl = MgCl2 + H2;

In accordance with the coefficients of the equation, when 1 mol of magnesium is dissolved, 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount of magnesium. To do this, divide the available weight of the metal by the weight of 1 mole of metal.

M Mg = 24 grams / mol;

N Mg = 16.8 / 24 = 0.7 mol;

The same amount of hydrogen will be synthesized.

Let’s calculate its volume, for this we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters):

V H2 = 0.7 x 22.4 = 15.68 liters;