Magnesium weighing 4.8 g reacted with 16 g of sulfuric acid. Determine the mass of the formed salt. (19.6 g)

univerkov | July 31, 2021 | education

Given:
m (Mg) = 4.8 g
m (H2SO4) = 16 g

To find:
m (salt) -?

1) Mg + H2SO4 => MgSO4 + H2;
2) n (Mg) = m / M = 4.8 / 24 = 0.2 mol;
3) n (H2SO4) = m / M = 16/98 = 0.16 mol;
4) n (MgSO4) = n (H2SO4) = 0.16 mol;
5) m (MgSO4) = n * M = 0.16 * 120 = 19.2 g.

Answer: The mass of MgSO4 is 19.2 g.

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