Magnesium weighing 4.8 g was dissolved in concentrated sulfuric acid. The obtained hydrogen sulfide was dissolved in 100 g

| June 22, 2021 | education

Magnesium weighing 4.8 g was dissolved in concentrated sulfuric acid. The obtained hydrogen sulfide was dissolved in 100 g of a 15% solution of copper (II) sulfate. Determine the mass of the sediment.

We write down the equation of reactions.
4Mg + 5H2SO4 = 4MgSO4 + H2S + 4H2O
Using the reaction equation, we find the mass of hydrogen sulfide.
4.8 g magnesium – x g hydrogen sulfide
24 * 4g / mol Mg – 34 g / mol H2S
X = 4.8 * 34: 24 * 4 = 1.7 g H2S.
Next, we write down the equation of reactions.
H2S + CuSO4 = CuS + H2SO4.
m (CuSO4) = 100 * 0.15 = 15 g.
n = m / M.
n = 1.7 / 34 = 0.05 mol H2S.
n = 15/160 = 0.09 mol CuSO4.
Hydrogen sulfide is in short supply, we consider hydrogen sulfide.
0.05 mol H2S – х mol СuS
1 mol H2S – 1 mol CuS
X (CuS) = 0.05 mol.
We find the mass.
m = 0.05 * 96 = 4.8 g CuS.
Answer: 4.8 g.



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