Make a thermochemical equation for the reaction of combustion of acetylene

Make a thermochemical equation for the reaction of combustion of acetylene, if it is known that the combustion of 1.12 liters of acetylene releases 65.25 kJ of heat.

Given:
V (C2H2) = 1.12 L
Q1 = 65.25 kJ
Vm = 22.4 l / mol

To find:
Thermochemical equation -?

Solution:
1) Calculate the amount of acetylene substance:
n (C2H2) = V (C2H2) / Vm = 1.12 / 22.4 = 0.05 mol;
2) Make up the proportion and calculate the amount of heat released, which corresponds to 1 mol of acetylene:
0.05 mol C2H2 – 65.25 kJ;
1 mol C2H2 – Q kJ;
Q = 1 * 65.25 / 0.05 = 1305 kJ;
3) Write the equation for the thermochemical reaction of the combustion of acetylene:
C2H2 + 21 / 2O2 => 2CO2 + H2O + 1305 kJ.