Make an equation and find the sides if the perimeter of triangle ABC is 68 cm AB is equal

Make an equation and find the sides if the perimeter of triangle ABC is 68 cm AB is equal to x cm BC is 2 times AB and AC is 7 cm less than BC.

The problem statement already contains x – this is the length of the side AB. Then the length of the side BC is 2x cm, and the length of AC is (2x – 7) cm.The perimeter of the triangle ABC is:

P = AB + BC + AC.

Hence, according to the conditions of the problem, the following equation can be drawn up:

x + 2x + (2x – 7) = 68.

Let’s solve it:

x + 2x + (2x – 7) = 68,

x + 2x + 2x – 7 = 68,

5x = 68 + 7,

5x = 75,

x = 75/5,

x = 15 cm.

We found the AB side. Next, we find the length of the side BC:

BC = 2 * 15 = 30 cm.

Now let’s find AC:

AC = 30 – 7 = 23 cm.

Answer: the sides of triangle ABC are equal: AB = 15 cm, BC = 30 cm and AC = 23 cm.



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