Make an equation for a circle whose diameter is AB, where A (-2; 3), B (4; 5)

The equation of the circle is (x – a) ^ 2 + (y – b) ^ 2 = R ^ 2
But since, according to the condition AB, is the diameter, we first find the center of the circle (midpoint of the segment) – point O.
O ((- 2-4) / 2; (3-5) / 2)
O (-3; -1)
AB ^ 2 = (x2-x1) ^ 2 + (y2-y1) ^ 2 = 36 + 4 = 40
AB = 2√10
Then R = √10
The equation of the circle is as follows:
(X + 3) ^ 2 + (Y + 1) ^ 2 = 10