Make an equation for the interaction of magnesium with sulfuric acid. Determine the oxidizing and reducing agent.

Make an equation for the interaction of magnesium with sulfuric acid. Determine the oxidizing and reducing agent. Calculate the mass of sulfuric acid required to completely dissolve 288 g of magnesium.

Given:
m (Mg) = 288 g

To find:
m (H2SO4) -?

Decision:
1) Write the reaction equation:
Mg + H2SO4 => MgSO4 + H2 ↑;
reducing agent – Mg0;
oxidizing agent – H +;
2) Calculate the molar mass of Mg and H2SO4:
M (Mg) = 24 g / mol;
M (H2SO4) = 98 g / mol;
3) Calculate the amount of Mg substance:
n (Mg) = m (Mg) / M (Mg) = 288/24 = 12 mol;
4) Determine the amount of substance H2SO4:
n (H2SO4) = n (Mg) = 12 mol;
5) Calculate the mass of H2SO4:
m (H2SO4) = n (H2SO4) * M (H2SO4) = 12 * 98 = 1176 g.

Answer: The mass of H2SO4 is 1176 g.