Make an equation for the reactions of interaction of copper with oxygen; iron with chloroma.
| December 19, 2020 | education
Make an equation for the reactions of interaction of copper with oxygen; iron with chloroma. Indicate the oxidation states of atoms, indicate the transition of electrons, as well as the oxidizing agent and reducing agent.
2Cu + O2 = 2CuO Cu ^ 0 – 2e -> Cu ^ + 2 O2 ^ 0 + 4e -> 2O ^ -2 Cu ^ 0 – reducing agent O2 ^ 0 – oxidizing agent 2Fe + 3Cl2 = 2FeCl3 Fe ^ 0 – 3e -> Fe ^ + 3 Cl2 ^ 0 + 2e -> 2Cl ^ – Fe ^ 0 – reducing agent Cl2 ^ 0 – oxidizing agent
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