Make an equation of a straight line passing through two points with coordinates A (4: 8) B (-6: -2).
July 22, 2021 | education
| To begin with, we write the equation of the straight line in general form:
y = kx + b.
If this straight line passes through a point with A coordinates (4; 8), then the following relation should be satisfied:
8 = 4k + b,
whence follows:
b = 8 – 4k
and the equation of the straight line takes the form:
y = kx + 8 – 4k.
If this straight line passes through a point with A coordinates (-6; -2), then the following relation should be fulfilled:
-6 = 2k + 8 – 4k,
whence follows:
2k + 4k = 8 + 6;
6k = 14;
k = 14/6 = 7/3.
Therefore, the required equation:
y = 7x / 3 + 8 – 4 * 7/3,
simplifying which, we get:
y = 7x / 3 + 8 – 28/3,
3y = 7x + 24 – 28;
7x – 3y – 4 = 0.
Answer: 7x – 3y – 4 = 0.
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