Make an equation of a straight line that passes through two points A (4; -1) and B (-6; 2).

The straight line equation has the form y = kx + b. We substitute the coordinates of points A and B into this equation and find k and b, we have a system of equations:

4k + b = -1;

-6k + b = 2.

Multiply the first equation by (-1), get -4k – b = 1 and add it to the second equation

-4k – b + (-6k) + b = 2 + 1;

-10k = 3;

k = 3: (-10);

k = – 0.3.

Substitute the value k = – 0.3 into the first equation of the system and find b, we get

4 * (-0.3) + b = -1;

-1.2 + b = -1;

b = -1 + 1.2;

b = 1.

Hence, the equation of the straight line will have the form y = -0.3x + 1.