Make an equation of the straight line passing through the point C (1; 2), parallel to the straight line AB

| April 11, 2021 | education

Make an equation of the straight line passing through the point C (1; 2), parallel to the straight line AB, where A (-1; 0) B (3; 1).

In general, the equation of the straight line is written as y = kx + b. Let’s compose the equation of the straight line on which two points A and B lie. Find the coefficient k and the free term b:

0 = (-1) * k + b,

1 = 3 * k + b.

b = k,

1 = 3k + k,

1 = 4k,

k = ¼.

Because b = k = ¼.

Thus, the line passing through the points will look like this:

y = 1 / 4x + 1/4.

The formula for a parallel straight line y – y0 = k (x – x0), where k is the slope of the straight line, x0, y0 are the coordinates of the point through which the graph passes. Find the formula for a parallel line, substituting the coordinates of the point: x0 = 1, y0 = 2.

y – 2 = 1/4 * (x – 1),

y – 2 = 1 / 4x – ¼,

y = 1 / 4x + 1 3/4.

Answer: the graph of the function y = 1 / 4x + 1 3/4.



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