Make an equation: SO2-SO3-H2SO4-Li2SO4-BaSO4

1) 2SO2 + O2 = 2SO3 (when sulfur (IV) oxide interacts with oxygen, sulfur (VI) oxide is formed);

2) SO3 + H2O = H2SO4 (when sulfur (VI) oxide interacts with water, sulfuric acid is formed);

3) H2SO4 + 2LiCl = Li2SO4 + 2HCl (when sulfuric acid reacts with lithium chloride, lithium sulfate and hydrochloric acid are formed);

4) Li2SO4 + Ba (OH) 2 = BaSO4 + 2LiOH (when lithium sulfate interacts with barium hydroxide, barium sulfate and lithium hydroxide are formed).



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