Make formulas for two ammonium salts, and write the molecular-ionic equations for their interaction

Make formulas for two ammonium salts, and write the molecular-ionic equations for their interaction with barium hydroxide.

1) Let’s compose the formulas of ammonium salts:

NH4Cl – ammonium chloride

(NH4) 2SO4 – ammonium sulfate

2) Let’s write the equation of the reaction between ammonium chloride and barium hydroxide in molecular form:

NH4Cl + Ba (OH) 2 = NH3 + H2O + BaCl2

Let’s arrange the coefficients:

2 NH4Cl + Ba (OH) 2 = 2 NH3 +2 H2O + Ba C l2

This reaction refers to exchange reactions, it proceeds to the end, because a gas is released – ammonia (NH3)

Let us write the reaction equation in full ionic form:

2 NH4 ^ (+) + 2 Cl ^ (-) + Ba ^ (2+) + 2 OH ^ (-) = 2 NH3 + 2 H2O + Ba ^ (2+) + 2 Cl ^ (-)

Let’s compose an abbreviated ionic equation for this reaction:

2 NH4 ^ (+) + 2 OH ^ (-) = 2 NH3 + 2 H2O

Reduce the coefficients by 2 and get

NH4 ^ (+) + OH ^ (-) = NH3 + H2O

3) We write the equation of the reaction between ammonium sulfate and barium hydroxide in molecular form:

(NH4) 2SO4 + Ba (OH) 2 = NH3 + H2O + Ba SO4

Let’s arrange the coefficients:

(NH4) 2SO4 + Ba (OH) 2 = 2 NH3 + 2 H2O + Ba SO4

This reaction belongs to exchange reactions, it proceeds to the end, because a gas is released – ammonia (NH3) and a precipitate of Ba SO4

Let us write the reaction equation in full ionic form:

2 NH4 ^ (+) + SO4 ^ (2-) + Ba ^ (2+) + 2 OH ^ (-) = 2 NH3 + 2 H2O + Ba SO4

The reaction does not have an abbreviated ionic equation, because all substances formed in the course of this reaction do not decay into ions.



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