Make formulas for two ammonium salts, and write the molecular-ionic equations for their interaction
Make formulas for two ammonium salts, and write the molecular-ionic equations for their interaction with barium hydroxide.
1) Let’s compose the formulas of ammonium salts:
NH4Cl – ammonium chloride
(NH4) 2SO4 – ammonium sulfate
2) Let’s write the equation of the reaction between ammonium chloride and barium hydroxide in molecular form:
NH4Cl + Ba (OH) 2 = NH3 + H2O + BaCl2
Let’s arrange the coefficients:
2 NH4Cl + Ba (OH) 2 = 2 NH3 +2 H2O + Ba C l2
This reaction refers to exchange reactions, it proceeds to the end, because a gas is released – ammonia (NH3)
Let us write the reaction equation in full ionic form:
2 NH4 ^ (+) + 2 Cl ^ (-) + Ba ^ (2+) + 2 OH ^ (-) = 2 NH3 + 2 H2O + Ba ^ (2+) + 2 Cl ^ (-)
Let’s compose an abbreviated ionic equation for this reaction:
2 NH4 ^ (+) + 2 OH ^ (-) = 2 NH3 + 2 H2O
Reduce the coefficients by 2 and get
NH4 ^ (+) + OH ^ (-) = NH3 + H2O
3) We write the equation of the reaction between ammonium sulfate and barium hydroxide in molecular form:
(NH4) 2SO4 + Ba (OH) 2 = NH3 + H2O + Ba SO4
Let’s arrange the coefficients:
(NH4) 2SO4 + Ba (OH) 2 = 2 NH3 + 2 H2O + Ba SO4
This reaction belongs to exchange reactions, it proceeds to the end, because a gas is released – ammonia (NH3) and a precipitate of Ba SO4
Let us write the reaction equation in full ionic form:
2 NH4 ^ (+) + SO4 ^ (2-) + Ba ^ (2+) + 2 OH ^ (-) = 2 NH3 + 2 H2O + Ba SO4
The reaction does not have an abbreviated ionic equation, because all substances formed in the course of this reaction do not decay into ions.