Make the electronic equations of the processes occurring on graphite electrodes during the electrolysis of a CdCl2

Make the electronic equations of the processes occurring on graphite electrodes during the electrolysis of a CdCl2 solution. Calculate the mass of cadmium released at the cathode if 280 ml of gas is released at the anode

Given:
V (gas) = 280 ml = 0.28 l
Vm = 22.4 l / mol

Find:
m (Cd) -?

Solution:
1) Write the equation of a chemical reaction:
CdCl2 <=> Cd2 + + 2Cl–;
K (-): Cd2 + + 2е = Cd0;
A (+): 2Cl– – 2e = Cl20;
CdCl2 = (electric current) => Cd + Cl2 ↑;
2) Calculate the amount of substance Cl2:
n (Cl2) = V (Cl2) / Vm = 0.28 / 22.4 = 0.0125 mol;
3) Determine the amount of substance Cd:
n (Cd) = n (Cl2) = 0.0125 mol;
4) Calculate the mass of Cd:
m (Cd) = n (Cd) * M (Cd) = 0.0125 * 112 = 1.4 g.

Answer: The mass of Cd is 1.4 g.