Make the equation: C3H7OH- C3H6- C3H6Br- C3H4- C3H5Cl- C3H5OH

Let us write down the equations for the transformation chain:
1. С3Н7ОН = Н2О + С3Н6 – dehydration reaction, propylene was formed;
2. С3Н6 + Br2 = C3H6Br2 – additions, dibromopropane was obtained;
3. С3Н6Br2 + 2NaOH = C3H4 + 2NaBr + 2H2O – propyne formed;
4. С3Н4 + НCl = H2C = CCl – CH3 – addition, 2-chloro propene is released;
5. Н2С = СCl – CH3 + KOH = H2C = C – OH – CH3 (C3H5OH) – exchange, unsaturated alcohol was obtained.
The given reactions show the connection of hydrocarbons and alcohols. The reaction products find practical applications, for example, dibromopropane as a solvent.



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