Make the equation: calcium carbide-acetylene-ethylene-ethanol-acetic acid-2 bromine acetic acid-ethyl ester-2 bromine acetic acid

Let’s write the equations:
CaC2 + 2H2O = Ca (OH) 2 + C2H2 – hydrolysis of calcium carbide leads to the formation of acetylene;
C2H2 + H2 = C2H4 – addition, ethylene was obtained;
С2Н4 + Н2О = С2Н5ОН – ethylene hydration, ethanol is released;
С2Н5ОН + CuO = CH3 – CHO + Cu + H2O – oxidation of ethanol, ethanal was formed;
CH3 – CHO + Ag2O = CH3COOH + 2Ag – silver mirror reaction, acetic acid was obtained;
CH3COOH + Br2 = BrCH2COOH + HBr – substitution, 2 bromine acetic acid is released;
CH2BrCOOH + C2H5OH = CH2BrCOO – C2H5 + H2O – esterification reaction.
These reactions confirm the connection of inorganic and organic substances, as well as the connection of hydrocarbons with oxygen-containing compounds.