Make the equation for the reactions of the interaction of hydrochloric acid (HCl)

Make the equation for the reactions of the interaction of hydrochloric acid (HCl) with zinc weighing 6.5 g. Calculate the amount of hydrogen evolved.

Reaction equation: Zn + 2HCl = ZnCl2 + H2
Let us find the amount of zinc substance n = m / M = 6.5 g / 65 g / mol = 0.1 mol. (M – molar mass, determined by the periodic table). According to the reaction from 1 mol of zinc, 1 mol of hydrogen is obtained, n (Zn) = n (H2) = 0.1 mol. Find the volume of hydrogen V = n * Vm = 0.1 mol * 22.4 l / mol = 2.24 l. (Vm – molar volume, constant for all gases under normal conditions). Answer: the volume of released hydrogen is 2.24 liters.