Make up the equations for the reactions of obtaining: a) methyl ester of acetic acid b) propyl ester of butyric acid

Let us write down the reaction equations for organic substances:
a) CH3OH + CH3COOH = CH3COO – CH3 + H2O – the esterification reaction is possible when heated in the presence of concentrated sulfuric acid, the methyl ester of acetic acid (methyl acetate) was obtained;
b) С3Н7ОН + С4Н9СООН = С3Н7СОО – С4Н9 + Н2О – esterification, occurs under normal conditions, sulfuric acid is added as a dehydrating agent, butyric acid propyl ester (propyl butyrate) is formed.
The reaction products, esters, are used as solvents for organic substances. The reactions show the linkage of alcohols, carboxylic acids, esters.