Let’s carry out the solution of the chain of transformations:
Methane – acetylene – benzene – bromobenzene
2CH4 = C2H2 + 3H2 – decomposition of methane, acetylene is released;
3C2H2 = C6H6 – trimerization occurs on a hot carbon catalyst, benzene is obtained;
C6H6 + Br2 = C6H5Br + HBr – substitution, benzene bromide is formed.
The solution process confirms the relationship of saturated hydrocarbons, alkynes (unsaturated) and aromatic. The transformation product, benzene bromide, is used as a solvent.
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