Make up the reaction equations illustrating the following transformations CL₂⇒HCL⇒CL₂⇒NaCL⇒HCL

Our first reaction is simple, we just add hydrogen. Don’t forget to call. 1) Cl2 + H2 -> 2HCl The second reaction is just as simple, we just need to add oxygen, remember the coefficients. 2) 4HCL + O2 -> 2H2O + Cl2 Since pure Sodium does not react with chrol, we will come to carry out a substitution reaction, for this I will take NaI and CL will replace I as a stronger halogen. 3) Cl2 + 2NaI -> 2NaCl + I2 And in order to get hydrochloric acid again, you just need to add water. 4) NaCl + H2O -> NaOH + HCl