Manganese oxide 2 valence weight 28.4 g was treated with a solution of nitric acid.

Manganese oxide 2 valence weight 28.4 g was treated with a solution of nitric acid. Calculate the amount and mass of the salt formed.

Let’s execute the solution:
In accordance with the condition, we write down the equation of the process:
MnO + 2HNO3 = Mn (NO3) 2 + H2O – ion exchange, manganese nitrate was formed;
Calculations by formulas:
M (MnO) = 70.9 g / mol;
M Mn (NO3) 2 = 178.9 g / mol.
Determine the amount of the original substance:
Y (MnO) = m / M = 28.4 / 70.9 = 0.4 mol;
Y Mn (NO3) 2 = 0.4 mol since the amount of substances is 1 mol.
Find the mass of salt:
m Mn (NO3) 2 = Y * M = 0.4 * 178.9 = 71.56 g
Answer: obtained manganese nitrate weighing 71.56 g