Manual force of 1 6-year-old boy 450N. What will be the impulse of force in 3 seconds of its action?
| January 6, 2021 | education
The given tasks: F (manual strength of a sixteen-year-old boy) = 450 N; t (duration of manual force) = 3 s.
To calculate the required impulse of force, we apply the formula: I = F * t.
Let’s perform the calculation: I = 450 * 3 = 1.35 * 10 ^ 3 H * s = 1.35 kN * s.
Answer: The impulse of force of a sixteen-year-old boy is 1.35 kN * s.
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