Medians AK, CM, BN are drawn in triangle ABC. Find the perimeter of triangle ABC if AM + CK + NC = 34.5 cm.
| May 30, 2021 | education
Since AK, BH and CM of the median of the triangle ABC, then AM = BM, BK = CK, AH = CH.
The perimeter of triangle ABC is equal to: Ravs = AB + BC + CH = (AM + BM) + (BK + CK) + (CH + AH) = 2 * AM + 2 * CK + 2 * CH = 2 * (AM + CK + CH) = 2 * 34.5 = 69 cm.
Answer: The perimeter of triangle ABC is 69 cm.
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