Merged two solutions of sulfuric acid: 200 g of 20% and 150 g of 3%. what is the satala

Merged two solutions of sulfuric acid: 200 g of 20% and 150 g of 3%. what is the satala mass fraction of acid in the resulting solution.

Given:
m1 solution (H2SO4) = 200 g
ω1 (H2SO4) = 20%
m2 solution (H2SO4) = 150 g
ω2 (H2SO4) = 3%

Find:
ω3 (H2SO4) -?

Solution:
1) m1 (H2SO4) = ω1 (H2SO4) * m1 solution (H2SO4) / 100% = 20% * 200/100% = 40 g;
2) m2 (H2SO4) = ω2 (H2SO4) * m2 solution (H2SO4) / 100% = 3% * 150/100% = 4.5 g;
3) m3 (H2SO4) = m1 (H2SO4) + m2 (H2SO4) = 40 + 4.5 = 44.5 g;
4) m3 solution (H2SO4) = m1 solution (H2SO4) + m2 solution (H2SO4) = 200 + 150 = 350 g;
5) ω3 (H2SO4) = m3 (H2SO4) * 100% / m3 solution (H2SO4) = 44.5 * 100% / 350 = 12.7%.

Answer: Mass fraction of H2SO4 is 12.7%.