Metallic sodium burns in oxygen to form sodium peroxide Na2O2. Write the reaction equation and determine
| November 30, 2020 | education
Metallic sodium burns in oxygen to form sodium peroxide Na2O2. Write the reaction equation and determine the mass fraction of which element in the peroxide is greater than sodium or oxygen?
2Na + O2 => Na2O2 the molar mass of peroxide is Mr (Na2O2) = 23 * 2 + 16 * 2 = 78 W (Na) = 46 \ 78 = 0.59 W (O2) = 32 \ 78 = 0.41 from which it follows that the mass fraction of sodium in sodium peroxide is greater than the mass fraction of oxygen
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