Mixed 100 ml of a 20% solution of sulfuric acid with a density of 1.14 g / ml and 400 g of a 5.2%

Mixed 100 ml of a 20% solution of sulfuric acid with a density of 1.14 g / ml and 400 g of a 5.2% solution of barium chloride. Determine the mass of the precipitated sediment.

Barium chloride reacts with sulfuric acid. At the same time, a water-insoluble barium sulfate salt is synthesized, which turns into an insoluble precipitate. The reaction is described by the following chemical reaction equation.

BaCl2 + H2SO4 = BaSO4 + 2HCl;

Barium chloride reacts with sulfuric acid in equal molar amounts. This produces the same amount of insoluble barium sulfate.

Let’s determine the chemical amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; N H2SO4 = 100 x 0.2 x 1.14 / 98 = 0.233 mol;

Let’s calculate the chemical amount of barium chloride.

M BaCl2 = 137 + 35.5 x 2 = 208 grams / mol; N BaCl2 = 400 x 0.052 / 208 = 0.1 mol;

Barium sulfate will be synthesized in the same molar amount (sulfuric acid is taken in excess).

Let’s calculate its weight.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; m BaSO4 = 0.1 x 233 = 23.3 grams;