Mixed 150 g of a solution with a mass fraction of sulfuric acid 10% and 250 g. A solution with a mass fraction

| June 23, 2021 | education

Mixed 150 g of a solution with a mass fraction of sulfuric acid 10% and 250 g. A solution with a mass fraction of sulfuric acid 8%. Determine the mass fraction of acid in the resulting solution.

We calculate the mass of the solute in the first solution using the following formula:

mr.v.1 = (mr-pa1 * wr.v.1) / 100% = (150 g * 10%) / 100% = 15 g.

We calculate the mass of the solute in the second solution using the same formula:

mr.c. 2 = (mr-ra2 * wr.c. 2) / 100% = (250 g * 8%) / 100% = 20 g.

The mass of the dissolved substance in the resulting solution:

mr.v. total = m.c. 1 + m.c. 2 = 15 g + 20 g = 35 g.

The mass of the resulting solution:

mr-ra total = mr-pa1 + mr-pa2 = 150 g + 250 g = 400 g.

Let’s find the mass fraction of acid in the resulting solution:

wr.v. = (mr.v. total * 100%) / mr-ra total. = (35 g * 100%) / 400 g = 8.75%.

Answer: 8.75%.



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