Mixed 200 g of a 10% solution and 300 g of a 30% salt solution. Determine the mass fraction of salt

Mixed 200 g of a 10% solution and 300 g of a 30% salt solution. Determine the mass fraction of salt in the newly obtained solution.

1.m1 (salts in 1 solution) = w1 (salts in 1 solution) * m1 (solution)

m1 (salts in 1 solution) = 0.1 * 200 = 20 g;

2. m2 (salts in 2 solutions) = w2 (salts in 2 solutions) * m2 (solutions);

m2 (salt in 2 solution) = 0.3 * 300 = 90 g;

3.the total mass of salt will be:

mtotal (salts) = m1 (salts in 1 solution) + m2 (salts in 2 solutions);

mtotal (salts) = 20 + 90 = 110 g;

4.find the mass of the solution after mixing:

mtotal (solution) = m1 (1 solution) + m2 (2 solution);

mtotal (solution) = 200 + 300 = 500 g;

5.Calculate the mass fraction of salt in the resulting solution:

w (salt) = mtot (salt): mtot (solution);

w (salt) = 110: 500 = 0.22 or 22%.

Answer: 22%.



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