Mixed solutions containing 22 g of calcium chloride and 15 g of phosphoric acid. Find the mass of the precipitate.

Let’s write down what we have: The mass is denoted by the letter m, we will write the mass of all substances Chloride is denoted as CaCl2 Phosphoric acid is denoted as H3PO4 So m (CaCl2) = 22g and m (H3PO4) = 15g We write the solution: (CaCl2) = m / M = 22 / 111 = 0.2 mol (Ca3 (PO4) 2) = 3/1 => 0.2 × 1/3 = 0.07 mol m (Ca3 (PO4) 2) = 0.07 × 310 = 21.7 g
Answer: the mass of the precipitated sediment is 21.7 g.