Mixed solutions of acetic acid weighing 200.300 and 400 g with a mass fraction of acid, respectively, 80

Mixed solutions of acetic acid weighing 200.300 and 400 g with a mass fraction of acid, respectively, 80, 40 and 15%. Determine the mass fraction of acetic acid in the resulting solution.

Given:
m1 solution (CH3COOH) = 200 g
m2 solution (CH3COOH) = 300 g
m3 solution (CH3COOH) = 400 g
ω1 (CH3COOH) = 80%
ω2 (CH3COOH) = 40%
ω3 (CH3COOH) = 15%

To find:
ω4 (CH3COOH) -?

Solution:
1) m1 (CH3COOH) = ω1 * m1 solution / 100% = 80% * 200/100% = 160 g;
2) m2 (CH3COOH) = ω2 * m2 solution / 100% = 40% * 300/100% = 120 g;
3) m3 (CH3COOH) = ω3 * m3 solution / 100% = 15% * 400/100% = 60 g;
4) m4 (CH3COOH) = m1 + m2 + m3 = 160 + 120 + 60 = 340 g;
5) m4 solution (CH3COOH) = m1 solution + m2 solution + m3 solution = 200 + 300 + 400 = 900 g;
6) ω4 (CH3COOH) = m4 * 100% / solution = 340 * 100% / 900 = 38%.

Answer: The mass fraction of CH3COOH is 38%.



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