# Mixed two solutions containing respectively 66.6 g of calcium chloride and 32.8 g of sodium phosphate.

**Mixed two solutions containing respectively 66.6 g of calcium chloride and 32.8 g of sodium phosphate. Calculate the mass of calcium phosphate formed.**

First, we write down the equation of the chemical reaction: 3CaCl2 + 2Na3PO4 = Ca3 (PO4) 2 + 6NaCl

Let’s calculate the amount of a substance of their formula n = m / M, where m is the mass of the compound, and M is its molar mass.

Molar mass CaCl2 = 111 g / mol, and Na3PO4 = 164 g / mol. n (CaCl2) = 0.6 mol, n (Na3PO4) = 0.2 mol. It can be seen that CaCl2 is in excess (2 mol of Na3PO4 requires 3 mol of CaCl2), which means that we are looking for the mass of the product by the amount of Na3PO4 from the formula m = n * M.

According to the equation n = 0.2 / 2 = 0.1, and M = 310 g / mol, then m = 31 g.