MN – midline of triangle ABC Find the side of AC if the perimeter of triangle MBN is 15, MB = 4, NC = 5.

Because MN is the middle line of the triangle, then it is equal to half the base of the triangle – AC. Therefore, to find AC, you first need to find MN.

The middle line of the triangle divides the chords in half, therefore BN = NC = 5.

Area of a triangle MBN = 15, therefore MN = P (triangle) – (MB + BN) = 15 – (4 + 5) = 6.

AC = MN × 2 = 6 × 2 = 12.

Answer: A = 12.



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