Molten zinc weighing 0.5 kg at a temperature of 420 degrees crystallizes and cools

Molten zinc weighing 0.5 kg at a temperature of 420 degrees crystallizes and cools down to 20 degrees. How much heat will be released at the same time

m = 0.5 kg.
t1 = 420 ° C.
t2 = 20 ° C.
C = 400 J / kg * ° C.
λ = 1.12 * 10 ^ 5 J / kg.
Q -?
Q -?
Q = λ * m + C * m * (t1 – t2).
Q = 1.12 * 10 ^ 5 J / kg * 0.5 kg + 400 J / kg * ° C * 0.5 kg * (420 ° C – 20 ° C) = 1.36 * 10 ^ 5 J.
Answer: during the crystallization and cooling of zinc, heat energy Q = 1.36 * 10 ^ 5 J.