Monovalent metal sulfate weighing 14.2 g was dissolved in water. The amount of SO4 (2-) ions

| June 26, 2021 | education

Monovalent metal sulfate weighing 14.2 g was dissolved in water. The amount of SO4 (2-) ions was found to be 0.1 mol. What metal sulphate was dissolved in water?

The equation for the electrolytic dissociation of an unknown monovalent metal sulfate:

M2SO4 = 2M + + SO42-, where M is an unknown monovalent metal.

According to the condition, the amount of the substance of sulfate anions:

v (SO42-) = 0.1 (mol).

Amount of substance M2SO4:

v (M2SO4) = m (M2SO4) / M (M2SO4) = 14.2 / (2 * M (M) + 96).

According to the dissociation equation, 1 mol of SO42- is formed per 1 mol of M2SO4, therefore: v (M2SO4) = v (SO42-).

Let’s compose and solve the equation:

14.2 / (2 * M (M) + 96) = 0.1,

whence M (M) = 23 (g / mol), which corresponds to the metal sodium (Na).

Answer: Na2SO4, sodium sulfate.



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