Moves with an accelerated movement of -0.6 m / s, the car stops 20 s after the start of braking

Moves with an accelerated movement of -0.6 m / s, the car stops 20 s after the start of braking, which is equal to the speed of the car at the beginning of braking.

The movement of the car is uniformly slow (a <0).

Vehicle speed:

V = V0 + at, where V is the final speed of the car (the car will stop, V = 0 m / s), V0 is the initial speed (m / s), a is the acceleration (a = -0.6 m / s2), t – braking time (t = 20 s).

Let’s express and calculate the speed of the car at the beginning of braking:

0 = V0 + at.

V0 = -at = – (-0.6) * 20 = 12 m / s.

Answer: The vehicle speed at the beginning of braking was 12 m / s.