Moving at a speed of 5 m / s, a hammer weighing 0.3 kg strikes a nail. Determine the average impact force if it lasts 0.15 s.

The given tasks: V (speed with which the taken hammer was moving) = 5 m / s; m (hammer weight) = 0.3 kg; t (duration of the blow to the nail) = 0.15 s.

To determine the average impact force of a taken hammer on a nail, we use the equality: m * V = F * t, whence F = m * V / t.

Let’s make a calculation: F = 0.3 * 5 / 0.15 = 10 N.

Answer: The average force of a blow of a taken hammer on a nail was 10 N.