Moving evenly in a straight line, the body has passed 200 cm in 10 s. How many hours does this body move

Moving evenly in a straight line, the body has passed 200 cm in 10 s. How many hours does this body move at the same speed and in the same direction to cover the distance of 36 km.

t1 = 10 s.

S1 = 200 cm = 2 m.

S2 = 36 km = 36000 m.

t2 -?

With uniform rectilinear movement, the time of movement t2 is determined by the ratio of the distance traveled S2 to the speed of movement V: t2 = S2 / V.

Since the body moved in the first and second cases with the same speed V, then its value will be expressed by the ratio of the traversed path S1 in the first case to the time of its passage t1: V = S1 / t1.

The formula for determining the transit time of the second section will take the form: t2 = S2 * t1 / S1.

t2 = 36,000 m * 10 s / 2 m = 180,000 s = 50 h.

Answer: the body will cover the path S2 = 36 km in time t2 = 50 hours.